New Maple Operators
Back on the movie set they are preparing a scene in which the clown is launched into flight inside a small capsule. It's the last scene of the movie, and where the clown thinks he's going to go in this capsule is unknown, but it certainly makes a nice set up for a sequel, which is what it's all about anyway. The capsule is launched towards the sea from a ramp on the beach. The ramp is at a 45 degree angle with the surface of the sea, and the capsule is accelerated a distance of 40 m along the ramp by a large compressed spring (The spring is compressed 40 m from equilibrium, and when not compressed the capsule end of the spring rests at the top edge of the ramp). Given that there is still no air on the set, that the coefficient of kinetic friction between the capsule and the surface of the ramp is .25, that the combined mass of the capsule, clown, and captive duck is 500 kg, and that the linear constant of the spring is 10,000 N/m, how fast is the capsule moving when it leaves the top end of the ramp? Solution Remember to use Maple help or the Maple
Index if you encounter a function or operator you do not remember.
Let the x-axis of the coordinate system lies along the surface of the ramp. > restart; Define the capsule as a system, and let the spring, the ramp, and the Earth be outside of the system. With these assumptions we can use the Work-Kinetic Energy Theorem to solve this problem. The Work-Kinetic Energy Theorem: The work done by the net external force on a body/system during a change in the body's position is equal to the change of kinetic energy of the body. > WKEThm := Work = Delta(KE);
The Greek letter Delta is used to indicate a change in a quantity, and
typically expressions like the change in kinetic energy would look like > Delta * KE := puppy_love; Error, invalid lhs of assignment So we'll stick with The definition of work is > Work := force * distance;
A spring generates a force that varies, and for situations of varying force the useful form of the Work equation is > Work := Int( net_force, r = r[i]..r[f] );
A change in kinetic energy is expressed mathematically as > Delta(KE) := (1/2)*mass*(v[f]^2-v[i]^2);
Thus, a useable form of the work kinetic energy theorem is > WKEThm;
Every vector equation resolves into a set of equations that expresses the situation in terms of component vectors which lie along the coordinate axes. There are two coordinate axes in our system and the two following equations express the above information in set form. > { Int(F[x], x=x[i]..x[f]) = (1/2)*mass*(v[x,f]^2-v[x,i]^2), Int(F[y], y=y[i]..y[f]) = (1/2)*mass*(v[y,f]^2-v[y,i]^2) };
Our choice of where to place the axes saves us from a lot of extra mathematics. Although the equation on the left correctly models its part of the situation, all we need is the equation on the right. Why? To simplify notation, make the following change to the Work equation. > Work := Int( F[x], x = x[i]..x[f] );
The WKEThm equation becomes > WKEThm;
Note that we are now also making the substitutions Rotating the picture above -45 degrees produces the following picture, and
using the information it provides, we can construct a useful expression for
> fric_force := mu*norm_force;
Where > norm_force := mass*10*cos(theta);
Thus, > 'fric_force' = fric_force;
> grav_force := mass*10*sin(theta);
> spr_force := -k*(x-x[equalib]);
The term > x[equalib] := 0;
and > 'spr_force' = spr_force;
Note that at this point we have made two choices about our coordinate axes which together have greatly simplified the mathematical representation of the problem. The net force along the x-axis is now represented as > F[x] := spr_force - grav_force - fric_force;
And with the following substitutions, > k := 10000; mass := 500; theta := Pi/4; mu := .25; x[i] := -40; x[f] := 0; v[i] := 0;
> 'F[x]' = F[x];
and WKEThm becomes > WKEThm;
> Work := value( Work );
> WKEThm;
> solve( WKEThm, v[f] );
As a check, > subs( v[f] = %[2], WKEThm );
> evalf( % );
As you are well aware, integration is a complicated and subtle process, and Maple employs many complicated and subtle algorithms to do integration. Unless instructed specifically on which technique to use, Maple uses some standard techniques. Blind trust of these algorithms without a good understanding of each of their assumptions and processes is a recipe for incorrect results. Until you know a lot more about different integration techniques and how to ask Maple to use them, never just accept any integration result that Maple produces. Although we did not in the problem above, which involved a definite integral of a rather simple polynomial, you should always make some check of the result of an int call for an even moderately complicated expression. In cases of indefinite integration use the diff function to differentiate the result and see if it produces the expression you originally integrated. When differentiating in these situations, Maple might return results that look nothing like the expression originally integrated. Don't immediately think that something is amiss; use the simplify function on the result first. Check out ?simplify and the related functions listed at the bottom of this help page.
Tutorial Index Maple Index How to... Problem Set Index
|